Asked by Jude
How many grams of glycerin C3H8O3 must be dissolved in 375.9g of water at 100 degrees Celsius to reduce the pressure of water above the solution to 714.6mmHg. The solution is a non-volatile compound
Answers
Answered by
DrBob222
Psoln = XH2O*P<sup>o</sup><sub>H2O
Psoln = 714.6 mm
P<sup>o</sup> H2O = 760 at the boiling point of 100 C and 1 atm pressure.
Solve for XH2O and substitute into the below equation.
Then XH2O = (nH2O)/(nH2O + nglycerin)
You can calculate nH2O from the problem. Solve for n glycerin and convert to grams. Post your work if you get stuck.
Psoln = 714.6 mm
P<sup>o</sup> H2O = 760 at the boiling point of 100 C and 1 atm pressure.
Solve for XH2O and substitute into the below equation.
Then XH2O = (nH2O)/(nH2O + nglycerin)
You can calculate nH2O from the problem. Solve for n glycerin and convert to grams. Post your work if you get stuck.
Answered by
Jude
Thank you DrBob222.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.