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Luisa and Connor had $360 altogether. after conner gave Luisa 3/5 of his money, she had the same amount of money as he did. how...Asked by kaykay
Luisa and Connor had $360 altogether. after conner gave Luisa 3/5 of his money, she had the same amount of money as he did. how much did conner have in the beginning?
Answers
Answered by
MathMate
Please check if there is a typo.
It is not possible that after Connor gave more than half of his money to Luisa and they still have an equal amount... unless Luisa had a negative amount (i.e. owes money) to start with.
It is not possible that after Connor gave more than half of his money to Luisa and they still have an equal amount... unless Luisa had a negative amount (i.e. owes money) to start with.
Answered by
kaykay
yes there is a typo it's supposed to be that he gave her 2/5 of his money.
Answered by
Ms. Sue
KayKay -- please check the links below the <b>Related Questions</b>.
Answered by
kaykay
I don't understand those answers and wanted to see of anyone explained it differently.
Answered by
MattsRiceBowl
Start by writing down what we know.
--There is $360 between two people.
--The names of the two people are Connor (which we will now call "C") and Luisa (we will call her "L").
--C gave L 2/5 of his money. They then had the same amount of money.
So let's break it down into what we can write for math. Since they both have $360, we can say if we add C and L's money together, there is $360.
C+L=360
We also know that if C gives L 2/5 of his money, they will have the same amount.
So L gets 2/5 of C's money.
L + 2/5C
That is equal to C losing 2/5 of his money (since he gave it to L)
C - 2/5C
Since they are now the same, we can put them together and say they are equal.
L + 2/5C = C - 2/5C
Now we have 2 equations:
L + 2/5C = C - 2/5C
AND
C+L = 360
Now what we want to do is put one letter by itself in any equation. (2nd one is easier to do).
C + L = 360
L = 360 - C
Now we can take that and change out the "C" in the other equation:
L + 2/5C = C - 2/5C
Anywhere we see a "L" we will change it to "360-C"
360-C + 2/5C = C - 2/5C
Now we just have to get C by itself.
360 = C - 2/5C + C - 2/5C
360 = 2C - 4/5C
360 = 1 1/5C
360 = 6/5 C
300 = C
So we know C had $300
The only question now is how much did L have?
Remember "C + L = 360?"
Since C had $300, we can say
300 + L = 360
L = 60
So C had $300
L had $60
Now we can check. C gave L 2/5 of his $$
300(2/5) = $120.
So C gave L $120, leaving him with $180.
L got $120. She had $60. So L NOW has $180
They both have the same amount.
Hope that helps. :-D
--There is $360 between two people.
--The names of the two people are Connor (which we will now call "C") and Luisa (we will call her "L").
--C gave L 2/5 of his money. They then had the same amount of money.
So let's break it down into what we can write for math. Since they both have $360, we can say if we add C and L's money together, there is $360.
C+L=360
We also know that if C gives L 2/5 of his money, they will have the same amount.
So L gets 2/5 of C's money.
L + 2/5C
That is equal to C losing 2/5 of his money (since he gave it to L)
C - 2/5C
Since they are now the same, we can put them together and say they are equal.
L + 2/5C = C - 2/5C
Now we have 2 equations:
L + 2/5C = C - 2/5C
AND
C+L = 360
Now what we want to do is put one letter by itself in any equation. (2nd one is easier to do).
C + L = 360
L = 360 - C
Now we can take that and change out the "C" in the other equation:
L + 2/5C = C - 2/5C
Anywhere we see a "L" we will change it to "360-C"
360-C + 2/5C = C - 2/5C
Now we just have to get C by itself.
360 = C - 2/5C + C - 2/5C
360 = 2C - 4/5C
360 = 1 1/5C
360 = 6/5 C
300 = C
So we know C had $300
The only question now is how much did L have?
Remember "C + L = 360?"
Since C had $300, we can say
300 + L = 360
L = 60
So C had $300
L had $60
Now we can check. C gave L 2/5 of his $$
300(2/5) = $120.
So C gave L $120, leaving him with $180.
L got $120. She had $60. So L NOW has $180
They both have the same amount.
Hope that helps. :-D
Answered by
Anonymous
"MattsRiceBowl" is correct!
Check again with a calculator first, though. :)
Check again with a calculator first, though. :)
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