Question
An aqueous solution of an unknown compound boils at 101.00 degrees Celsius (760 torr). What is the molality, and freezing point of this solution?
Answers
delta T = 101-100 = ??
delta T = Kb*molality
Solve for molality.
Now use the molality in the freezing point equation.
delta T = Kf*m
You have Kf and m, solve for delta T and convert to freezing point knowing the normal freezing point is zero C.
delta T = Kb*molality
Solve for molality.
Now use the molality in the freezing point equation.
delta T = Kf*m
You have Kf and m, solve for delta T and convert to freezing point knowing the normal freezing point is zero C.
20
1000.0
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