When (R)-butan-2-ol is treated with TsCl in pyridine and the tosylated alcohol is treated with sodium chloride in acetone we expect an inversion of the chiral centre and a 2-chlorobutane to be formed. There is no 2-chlorobutane in the list so
E)none of these.
There will also be some elimination reaction to form butene, but again there is no butene in the list.
Could someone help out with this question. Im stuck on it. Thanks
When (R)-butan-2-ol is treated with TsCl in pyridine and the tosylated alcohol is treated with sodium chloride in acetone, the resulting product is:
A) (R)-2-iodobutane
B) (S)-2-iodobutane
C) 2-iodobutane (racemic)
D) 1-butane
E) None of these
I think its choice B or C, but im not sure.
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