Asked by Lily
can you please check my answers??
9.
For the following reaction delta H=2816 kj.
6 CO2(g) + 6 H2O(l) -> C6H12O6(s) + 6O2(g)
how is the equilibrium yeild of C6H12O6(s)affected by each of the following?
a) increasing pressure of CO2
increase
decrease
no effect
Answer: increase?
b)increasing temp
increase
decrease
no effect
Answer: increase?
c) removing CO2
increase
decrease
no effect
Answer: decrease?
d) decreasing the total pressure
increase
decrease
no effect
answer: decrease?
e) removing part of the C6H12O6
increase
decrease
no effect
Answer: no effect
f) adding a catalyst
increase
decrease
no effect
answer: no effect
thanks so much!!!
9.
For the following reaction delta H=2816 kj.
6 CO2(g) + 6 H2O(l) -> C6H12O6(s) + 6O2(g)
how is the equilibrium yeild of C6H12O6(s)affected by each of the following?
a) increasing pressure of CO2
increase
decrease
no effect
Answer: increase?
b)increasing temp
increase
decrease
no effect
Answer: increase?
c) removing CO2
increase
decrease
no effect
Answer: decrease?
d) decreasing the total pressure
increase
decrease
no effect
answer: decrease?
e) removing part of the C6H12O6
increase
decrease
no effect
Answer: no effect
f) adding a catalyst
increase
decrease
no effect
answer: no effect
thanks so much!!!
Answers
Answered by
bobpursley
a) nope, there are equal volumes of gases on each side.d) is the same reason.
all others are correct.
all others are correct.
Answered by
Lily
So for a and d are you saying there is no effect?
Answered by
DrBob222
Yes, a and d are no effect.
Answered by
Loco
Actually, a is not no effect
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