Asked by Jeromino
Evaluate
log(base2)8-log(base2)12+log(base2)6
log(base2)8-log(base2)12+log(base2)6
Answers
Answered by
MathMate
Use the laws of logarithm:
log(a)+log(b)=log(ab)
log(a)-log(b)=log(a/b)
so
log(base2)8-log(base2)12+log(base2)6
=log(base2)(8/12*6)
=log(base2)4
=2
log(a)+log(b)=log(ab)
log(a)-log(b)=log(a/b)
so
log(base2)8-log(base2)12+log(base2)6
=log(base2)(8/12*6)
=log(base2)4
=2
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