Z = (mean1 - mean2)/standard error (SE) of difference between means
SEdiff = √(SEmean1^2 + SEmean2^2)
SEm = SD/√(n-1)
If only one SD is provided, you can use just that to determine SEdiff.
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion
The highest acceptable level of pesticide found in quail has been limited to 0.35 parts per million (ppm). A hunting organization measured the level of the pesticide found in a random sample of 20 quail harvested from field trials. The sample produced a sample mean of .44. Assume that the population standard deviation is 0.21 ppm. Using alpha [] = 0.05, does the data provide sufficient evidence to conclude that the mean level of pesticide is greater that the limit of 0.35 ppm?
2a. Use the critical value z0 method to test the hypothesis.
(References: example 7 through 10 pages 385 - 388, end of section exercises 39 – 44 pages 392 - 393) (6 points)
H0: u≤0.35
Ha: u>0.35
Critical z0:
Decision:
Interpretation:
1 answer
1 answer