Asked by Dave

I'm asked to find the shortest wavelength photon emitted for the paschen series for the hydrogen atom. I used the Rydberg equation and substituted the appropriate values.

Frequency= Rh(1/3^2)-(1/infinity^2)

I get an answer of 820 nm. My online homework program said this answer was wrong, but I feel pretty confident I'm doing this right. What am I doing wrong?

Answers

Answered by bobpursley
The Rydberg equation is

1/wavelength= R(1/n^2)

1/wavelength=1.097E7(1/9)

wavelength=820.3nm is the shortest.
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