The Rydberg equation is
1/wavelength= R(1/n^2)
1/wavelength=1.097E7(1/9)
wavelength=820.3nm is the shortest.
I'm asked to find the shortest wavelength photon emitted for the paschen series for the hydrogen atom. I used the Rydberg equation and substituted the appropriate values.
Frequency= Rh(1/3^2)-(1/infinity^2)
I get an answer of 820 nm. My online homework program said this answer was wrong, but I feel pretty confident I'm doing this right. What am I doing wrong?
1 answer