Asked by ANNA-MARIE

When NO(g) (0.06623 mol/L) and 422.6 grams of Cl2(g) in a 180.0 L reaction vessel at 565.0 °C are allowed to come to equilibrium the mixture contains 3.096 mol of NOCl(g). What is the concentration (mol/L) of NOCl(g)?
2NO(g)+Cl2(g) = 2NOCl(g)
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