Question

When SbCl3(g) (4.867 mol) and 0.01217 mol/L of Cl2(g) in a 400.0 L reaction vessel at 958.0 K are allowed to come to equilibrium the mixture contains 0.008586 mol/L of SbCl5(g). What concentration (mol/L) of SbCl3(g) reacted?
SbCl3(g)+Cl2(g) = SbCl5(g)

Unit Conversions:
K = C + 273
Molar Mass (g/mol)
SbCl3(g) 228.16
Cl2(g) 70.906
SbCl5(g) 299.06

Related Questions

In a reaction vessel, the following reaction was carried out using 0.250 mol of NH3 and 0.100 mol of... In a reaction vessel, the following reaction was carried out using 0.250 mol of NH3(l) and 0.100 mol... The following reaction was carried out in a 2.00 reaction vessel at 1100 : C+H2O -> C)+H2 If dur... when a 2 litre reaction vessel in which 15 grammes of pcl5 had been placed and mantained at 250 degr...