Asked by hannia

hello i need help with system of equations theres 3 only thank you
2x+3y-17
3x+y=31

2(x-3y)=24
y=3x-2

2(x+4)=24
x+y=17
Answered by Damon
2x+3y=17 I assume
3x+y=31
try elimination
multiply the entire first equation by 3 to get 6x term
multiply the entire second equation by 2 to get 6x term
so:
6x+9y = 51
6x+2y = 62
----------- subtract
7 y = -11
y = -11/7
then 2x = 17+33/7
x = 152/14 = 76/7

check
3(76/7) -11/7 = 31, right
Answered by Damon
for the second one you already have y as a function of x so use substitution
2(x-3y)=24 ---> x - 3y = 12
y=(3x-2 )

x - 3(3x-2) = 12
-8 x + 6 = 12
-8 x = 6
x = -3/4 etc

Answered by Anonymous
are you sure whatb grade are you in
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