on the slope, there are three forces
Force pushing- force down the plane-frictional force= ma assuming constant speed, (a=0) then
force pushing= mgSin30+friction. If you assume rolling friction is zero, you have it.
Now, if stopped
mgsin30=frictional force
this seems too easy.
A patient of mass 75kg sits in a wheelchair of mass 30kg. What is the force needed to push both up a 30 degree slope? If the carer stops on the 30 degree slope and applies the brake, what is the magnitude and direction of the frictional force preventing the wheelchair from rolling back down?
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