Asked by Mikie

A charge of 0.25 C moved from a position where the electric potential is 20 V to a position where the potential is 50 V. What is the change in potential energy?

Answers

Answered by bobpursley
work= PE1-PE= q1V1-q2V2=.25 (-30)=-7.5J

PE change = - work done
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions