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Asked by Mikie

A charge of 0.25 C moved from a position where the electric potential is 20 V to a position where the potential is 50 V. What is the change in potential energy?
14 years ago

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Answered by bobpursley
work= PE1-PE= q1V1-q2V2=.25 (-30)=-7.5J

PE change = - work done
14 years ago

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