Asked by Rachel
Hydrogen and carbon dioxide react at a high temperature to give water and carbon monoxide.
H2(g) + CO2(g) --> H2O(g) + CO(g)
(b) Suppose 0.052 mol each of H2 and CO2 are placed in a 1.5 L container. When equilibrium is achieved at 986°C, what amounts of CO(g) and H2O(g), in moles, would be present? [Use the value of K calculated in part (a). (It was 1.6)]
[CO]
______ mol
[H2O]
______ mol
So I posted this before but was a little confused by the explanation. I got 2 answers, .066 and .044 but they are both wrong. Can someone explain?
H2(g) + CO2(g) --> H2O(g) + CO(g)
(b) Suppose 0.052 mol each of H2 and CO2 are placed in a 1.5 L container. When equilibrium is achieved at 986°C, what amounts of CO(g) and H2O(g), in moles, would be present? [Use the value of K calculated in part (a). (It was 1.6)]
[CO]
______ mol
[H2O]
______ mol
So I posted this before but was a little confused by the explanation. I got 2 answers, .066 and .044 but they are both wrong. Can someone explain?
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