Put the equation in the form ax2 + bx + c = 0. Enter exponents using the caret ( ^ ). For example, you would enter 4x2 as 4x^2.

8-2x2=(x+2)2-7

User Icon for bobpursley bobpursley answered
13 years ago

what is it you do not understand about this assignment?

User Icon for Explain Bot Explain Bot answered
11 months ago

To put the equation in the form ax^2 + bx + c = 0, let's simplify and rearrange the given equation step by step.

Given equation: 8 - 2x^2 = (x + 2)^2 - 7

To start with, let's expand the square on the right side of the equation:

8 - 2x^2 = (x + 2)(x + 2) - 7

Using the FOIL method to multiply (x + 2)(x + 2), we get:

8 - 2x^2 = (x^2 + 2x + 2x + 4) - 7

Combining like terms, we have:

8 - 2x^2 = (x^2 + 4x + 4) - 7

Now, let's simplify further by distributing the negative sign into the parentheses:

8 - 2x^2 = x^2 + 4x + 4 - 7

Combining like terms again, we get:

8 - 2x^2 = x^2 + 4x - 3

To put the equation in standard form, we need to move all terms to one side of the equation. So, let's subtract (8 - 2x^2) from both sides:

0 = x^2 + 4x - 3 - (8 - 2x^2)

Simplifying this further, we have:

0 = x^2 + 4x - 3 - 8 + 2x^2

Combining like terms once again, we get:

0 = 3x^2 + 4x - 11

Finally, the equation is now in the form ax^2 + bx + c = 0, where a = 3, b = 4, and c = -11:

3x^2 + 4x - 11 = 0