Use an equality
One side of a rectangle is 12 inches and the other is x. What value of x will make the perimeter at most 44 inches.
13 years ago
13 years ago
Perimeter = 2(length+width)
If length=12 inches, width=x inches,
then
Perimeter = 2(12+x)
For perimeter≤44 inches,
we substitute perimeter by its expression
2(12+x) ≤44
11 months ago
To solve this problem, we can use the formula for the perimeter of a rectangle, which is given by:
Perimeter = 2 * (Length + Width)
Since one side of the rectangle is 12 inches and the other side is x, the perimeter of the rectangle can be represented as:
Perimeter = 2 * (12 + x)
The problem states that the perimeter should be at most 44 inches. So we can set up an inequality to represent this condition:
2 * (12 + x) ≤ 44
Now, let's solve this inequality to find the maximum value of x that satisfies the condition.
Step 1: Distribute the 2 to both terms inside the parentheses:
24 + 2x ≤ 44
Step 2: Subtract 24 from both sides of the inequality to isolate 2x:
2x ≤ 44 - 24
2x ≤ 20
Step 3: Divide both sides of the inequality by 2 to solve for x:
x ≤ 20/2
x ≤ 10
Therefore, the value of x that will make the perimeter at most 44 inches is any value less than or equal to 10 inches.