Asked by marie
topic: thermochemistry
i'm not really sure how to go about his question. i'm not sure with formula to use. (perhaps Cspht= q/(m x deltaT)?)can you please help me step by step or give me a hint and i'll post my answer, pretty please?
"250g of hot coffee at 95 degree celsius are placed in a 0.200 kg mug at 20 degree celsius. The specific heat of the coffee is 4.00 Jg^-1K^-1 while that of the mug is 0.80 Jg^-1K^-1. Assuming that no heat is lost to the surroundings, what is the final temperature of the mug+coffee system?"
i'm not really sure how to go about his question. i'm not sure with formula to use. (perhaps Cspht= q/(m x deltaT)?)can you please help me step by step or give me a hint and i'll post my answer, pretty please?
"250g of hot coffee at 95 degree celsius are placed in a 0.200 kg mug at 20 degree celsius. The specific heat of the coffee is 4.00 Jg^-1K^-1 while that of the mug is 0.80 Jg^-1K^-1. Assuming that no heat is lost to the surroundings, what is the final temperature of the mug+coffee system?"
Answers
Answered by
bobpursley
The sum of the heats gained is zero.
Heat gained by mug+heat gained by coffee=0
massmug*Cmug*(Tf-20)+masscoffee*Cwater*(Tf-95)=0
solve for Tf
Heat gained by mug+heat gained by coffee=0
massmug*Cmug*(Tf-20)+masscoffee*Cwater*(Tf-95)=0
solve for Tf
Answered by
marie
oh! i get it now. q mug + q coffee = 0
after typing many numbers on my calculator i got the final temperature to equal 84.65 degrees C. I'm sure this is right, thank you very much :)
after typing many numbers on my calculator i got the final temperature to equal 84.65 degrees C. I'm sure this is right, thank you very much :)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.