Question

. Given the following stocks 4M NaCl, 3M NaOH, 5M HCl
(a) Prepare 200ml of a solution containing 0.5M NaCl and 0.1M
(b) Prepare 300ml of a solution containing 0.5M NaCl
(c) Prepare 200ml of a solution containing 0.5M NaCl and 0.1M HCl

Answer 1

Your questin is messed up on a.

c. you want one part stock NaCl, 7 parts other. But you also want (5/.1) a dilution of 5O for the stock HCl, so one part of HCL is 200/50=4ml, so add 4ml of stock HCl, now the remainder water:
Remainder=200-6-50=144ml water.
You now have .5MNaCl with .1MHCl, a very odd combination.

Answer 2

Answer