Asked by Sam
Three quarters are tossed and a tail appears on at least one of them. What is the probability that at least one head appears? Express as a common fraction.
Answers
Answered by
YOSHI
2/3, because there are 3 coin flips, but one is already tails, so there's only 2 more chances to get heads.
Answered by
S_Dog
Well basically, just count how many total combinations there are in the flips.
= HHH, HHT, HTH, THH, TTH, THT, HTT, TTT
Of those, we find 7 with a tail (we omit HHH from our list).
Now with that, we count the ones with at least one head.
So..our answer is 6/7
= HHH, HHT, HTH, THH, TTH, THT, HTT, TTT
Of those, we find 7 with a tail (we omit HHH from our list).
Now with that, we count the ones with at least one head.
So..our answer is 6/7
Answered by
Anonymous
There are a total of eight possible outcomes for three coins: HHH, HHT, HTH, THH, TTH, THT, HTT, and TTT. Of these eight outcomes, seven of them show at least one tail (all except HHH).
Counting, we find six of these seven outcomes have at least one head, so the probability is 6/7.
Counting, we find six of these seven outcomes have at least one head, so the probability is 6/7.
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