Asked by Stefan
Microwaves of wavelength 4.50 cm enter a long, narrow window in a building that is otherwise essentially opaque to the incoming waves. If the window is 36.5 cm wide, what is the distance from the central maximum to the first-order minimum along a wall 6.70 m from the window?
Answers
Answered by
bobpursley
a sintheta=1*lambda
but sinTheta=tantheta=distance/6.70
.0365*distance/6.7=lambda=.0450
solve for distance in meters.
but sinTheta=tantheta=distance/6.70
.0365*distance/6.7=lambda=.0450
solve for distance in meters.
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