Asked by maddie
what sample size of .9181M vinegar would require 27.50 mL of .5185M of NaOH for neutralization?
Answers
Answered by
DrBob222
How many moles NaOH do you have? That is M x L = ??
How many moles vinegar do you have? That will be the same as the number of moles NaOH since the equation is a 1:1 ratio.
CH3COOH + NaOH ==> H2O + CH3COONa
Then M vin = moles vin/L vin and solve for L vinegar.
How many moles vinegar do you have? That will be the same as the number of moles NaOH since the equation is a 1:1 ratio.
CH3COOH + NaOH ==> H2O + CH3COONa
Then M vin = moles vin/L vin and solve for L vinegar.
Answered by
Mateo
Thanks Dr.Bob!
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