Asked by anjai
in a triangle ABC, C=10CM A=12CM ANGLE B Is 20 DEGREEZ calculate the lenght of side b
Answers
Answered by
Henry
The Law of Cosines:
CosB = (a^2 + c^2 - b^2) / 2ac,
0.9397 = ((12)^2 +(10)^2 - b^2) / 240,
0.9397 = (144 + 100 - b^2) / 240,
0.9397 = (244 - b^2) / 240,
244 - b^2 = 225.53,
-b^2 = 225.53 - 244 = -18.47,
b = 4.3.
CosB = (a^2 + c^2 - b^2) / 2ac,
0.9397 = ((12)^2 +(10)^2 - b^2) / 240,
0.9397 = (144 + 100 - b^2) / 240,
0.9397 = (244 - b^2) / 240,
244 - b^2 = 225.53,
-b^2 = 225.53 - 244 = -18.47,
b = 4.3.
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