Asked by cheryl
If a high schol base ball player average pitching speed is 50 ft. in .63 sec. and the average pitch drops 9 mph over 10 ft.
What is the player's pitching speed in 50 ft. equivalence(rounded to the tenth).
What is the player's pitching speed in 50 ft. equivalence(rounded to the tenth).
Answers
Answered by
Aaron
50 ft per .63 sec = 79.3651 ft per sec
79.3651 ft per sec = 54.112568 mph
every 10 ft the speed drops 9 mph, so 54.112568 mph - (5 x 9) = 9.112568 mph
I'm not sure I understood the question completely, but I think this is the right answer.
79.3651 ft per sec = 54.112568 mph
every 10 ft the speed drops 9 mph, so 54.112568 mph - (5 x 9) = 9.112568 mph
I'm not sure I understood the question completely, but I think this is the right answer.
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