How would you go about solving this? Im totally confused. Thanks!

Question

Find the value of k such that the graph of f contains the given point. Write k as a simplified fraction if it is not a whole number.

f(x) = kx^3 - 3x^2 + kx + 3; (-1, 8)

Answer 1

Y = K(-1)^3-3(-1)^2+K(-1)+3 = 8,
-K-3-K+3 = 8,
-2K = 8,
K = -4.