Asked by Lexi
How would you prepare 1.00 liter of a 0.18 M solution of NaOh?
Answers
Answered by
bobpursley
I would do this:
massNaoh= molarity*volume*molemassNaOH
= .18*1*figureitout
then, add the NaOH to 1 liter of water, stir until dissolved, label the container with contents, concentration,date prepared, hazards, and storage requirements if needed.
This was a test question often on my tests, and a lab quiz.
massNaoh= molarity*volume*molemassNaOH
= .18*1*figureitout
then, add the NaOH to 1 liter of water, stir until dissolved, label the container with contents, concentration,date prepared, hazards, and storage requirements if needed.
This was a test question often on my tests, and a lab quiz.
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