A baseball player pops a pitch straight up. The ball (mass 160 g) was traveling horizontally at 32.0 m/s just before contact with the bat, and 24.0 m/s just after contact. Determine the magnitude of the impulse delivered to the ball by the bat.

Answer 1

The impulse equals the change in momentum. It will be the be the hypotenuse of a 3:4:5 right triangle of momentum.

That would make it 40 m/s *0.16 kg
= 6.4 kg m/s