Asked by cloey
A baseball player pops a pitch straight up. The ball (mass 160 g) was traveling horizontally at 32.0 m/s just before contact with the bat, and 24.0 m/s just after contact. Determine the magnitude of the impulse delivered to the ball by the bat.
Answers
Answered by
drwls
The impulse equals the change in momentum. It will be the be the hypotenuse of a 3:4:5 right triangle of momentum.
That would make it 40 m/s *0.16 kg
= 6.4 kg m/s
That would make it 40 m/s *0.16 kg
= 6.4 kg m/s
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