A resitor of unknown resistance and a 35-omega resistor are connected across a 120-V emf device in such a way that an 11-A current flows. What is the value of the unknown reisistance?

No more than 120/35 = 3.43 A could flow if the resistors were in series. Theretore I mus assume that they are in parallel and that 11-3.43 = 7.57 A flows through the unknown resistor. Use that fact and the 120 V applied voltage to get its resistance, R = V/I = 15.85 ohms

To determine the value of the unknown resistance in this circuit, we can apply Ohm's Law and Kirchhoff's Laws. Here's how you can calculate it step by step:

Step 1: Write down the given values:
- Voltage (emf) across the circuit (V_emf) = 120 V
- Known resistance (R2) = 35 Ω
- Current flowing through the circuit (I) = 11 A

Step 2: Apply Ohm's Law:
Ohm's Law states that the voltage across a resistor is equal to the current flowing through it multiplied by its resistance.

V = I * R

In this case, we can apply Ohm's Law to the known resistance (R2):

V_R2 = I * R2

Step 3: Substitute the known values:
V_R2 = 11 A * 35 Ω

V_R2 = 385 V

Step 4: Apply Kirchhoff's Laws:
Kirchhoff's Voltage Law (KVL) states that the sum of voltages around a closed loop in a circuit should be zero.

In this circuit, the total voltage (emf) across the circuit is equal to the sum of the voltages across the individual resistances:

V_emf = V_R1 + V_R2

Step 5: Substitute the known values:
V_emf = V_R1 + 385 V

V_emf = 120 V

Step 6: Solve for the unknown resistance:
Rearrange the equation from Step 5 to isolate the unknown resistance (R1):

V_R1 = V_emf - V_R2

R1 = (V_emf - V_R2) / I

Substitute the known values:

R1 = (120 V - 385 V) / 11 A

R1 = -265 V / 11 A

R1 ≈ -24.1 Ω

Since resistance can't be negative, it seems like there's an error in the calculations or setup of the circuit.

Double-check the calculations and the information provided to ensure accuracy.