Asked by Nana

What is the pH of a solution that is 0.40 M in sulfurous acid (H2SO3) and )0.22 M in sodium sulfite (NaHSO3-)? Ka (H2SO3) = 1.3x10-2

Answers

Answered by DrBob222
Use the Henderson-Hasselbalch equation.
pH = pKa + log (base)/(acid).
Answered by Nana
Thanks :) I did that and got 1.63 as my pH, which is the correct answer.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions