What is the pH of a solution that is 0.40 M in sulfurous acid (H2SO3) and )0.22 M in sodium sulfite (NaHSO3-)? Ka (H2SO3) = 1.3x10-2

Answer 1

Use the Henderson-Hasselbalch equation.
pH = pKa + log (base)/(acid).

Answer 2

Thanks :) I did that and got 1.63 as my pH, which is the correct answer.