(P1V1/T1) = (P2V2/T2)
P1 = 800 torr - vapor pressure water @ 25C.
P2 = Standard P
V1 = 4.36L
V2 = Solve for this.
T1 = 298 K
T2 = 273K
A sample of methane gas, CH4, was collected over water at 25.0ºC and 800 torr. The volume of the wet gas is 4.36 L. What will be the volume of the dry methane at standard pressure?
Voldry methane=_______L
1 answer