Question

In the sport of pole vaulting, the jumper's point of mass concentration, called the centre of mass, must clear the pole. Assume that a 59 kg jumper must raise the centre of mass from 1.1 m off the ground to 4.6 m off the ground. What is the jumper's potential energy at the top of the bar relative to the point at which the jumper started to move?

Answer 1

P.E. change = M*g*(change in H)

Answer 2

In the sport of pole vaulting, the jumper's point of mass concentration, called the centre of mass, must clear the pole. Assume that a 59 kg jumper must raise the centre of mass from 1.1 m off the ground to 4.6 m off the ground. What is the jumper's potential energy at the top of the bar relative to the point at which the jumper started to move?

can you please show step by step what to do with solutions
thanks it would be great help

Answer 3

This is a one step problem. Use the formula I provided to calculate the Potential Energy change at the top of the jump.

Answer 4

so i did Ep=Mg (hf-hi)
=59(9.8)(4.6-1.1)
=2023.7 J

is this right