Find the perimeter of a regular hexagon that has an area of 54 radical 3 units squared.

Answer 1

In wikipedia type hexagon

Area:

A=t^2*[3*sqroot(3)]/2

54*sqroot(3)=t^2*[3*sqroot(3)]/2

Divide booth sides with sqroot(3)

54=3*t^2/2

54*2=3t^2
108=3t^2 Divide booth sides with 3

108/3=t^2

t^2=36

t=6

Perimeter:

P=6*t=6*6=36