Asked by Haley
solve the system of equations:
x^(2)+y^(2) = 12
xy = -4
x^(2)+y^(2) = 12
xy = -4
Answers
Answered by
drwls
Use substitution.
y = -4/x
x^2 + 16/x^2 = 12
let u = x^2
u + 16/u = 12
u^2 -12u + 16 = 0
u = (1/2)[12 +/-sqrt80]
= 10.47 or 1.527
x = +/-1.236 or +/-3.236
Get y for each x using
y = -4/x
y = -4/x
x^2 + 16/x^2 = 12
let u = x^2
u + 16/u = 12
u^2 -12u + 16 = 0
u = (1/2)[12 +/-sqrt80]
= 10.47 or 1.527
x = +/-1.236 or +/-3.236
Get y for each x using
y = -4/x
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