1/2 is 2 to the -1 power.
Therefore y = -1
log(subscript 2)(0.5)
I know how to convert it into:
0.5 = 2^(y)
but then how do I find y?
8 answers
How do you just know this though?
Because for any number a,
a^-1 = 1/a
and because 0.5 = 1/2.
These are things you know already
a^-1 = 1/a
and because 0.5 = 1/2.
These are things you know already
okay.
how would you solve:
2log(subscript6)(4) - (1/3)log(sub6)(8) = log(sub6)(x)
how would you solve:
2log(subscript6)(4) - (1/3)log(sub6)(8) = log(sub6)(x)
2log(sub6)(4) - (1/3)log(sub6)(8)
= log(sub6)(x)
log(sub6)[4^2 / 8^1/3] = log(sub6)x
log(sub6)[16/2] = log(sub6)8
= log(sub6) x
Therefore x = 8
= log(sub6)(x)
log(sub6)[4^2 / 8^1/3] = log(sub6)x
log(sub6)[16/2] = log(sub6)8
= log(sub6) x
Therefore x = 8
so the coefficient of a log function are the same as writing it as an exponent of x in the equation: log(subb)x = y ?
therefore, Clog(subb)x = y is the same as log(subb)x^(C) = y ?
therefore, Clog(subb)x = y is the same as log(subb)x^(C) = y ?
What you wrote is true.
Remember that log x^a = a log x, no matter what the log base is, as long as it is the same base on both sides.
However, what I am also saying is that if
Log(suba) x = Log(suba)y, then x = y
no matter what the base a is.
Remember that log x^a = a log x, no matter what the log base is, as long as it is the same base on both sides.
However, what I am also saying is that if
Log(suba) x = Log(suba)y, then x = y
no matter what the base a is.
end of lesson