Question
For propanoic acid (HC3H5O2, Ka = 1.3 10-5), determine the concentration of all species present, the pH, and the percent dissociation of a 0.29 M solution.
[H+]
[C3H5O2-]
[OH -]
[HC3H5O2]
pH
percent dissociation
[H+]
[C3H5O2-]
[OH -]
[HC3H5O2]
pH
percent dissociation
Answers
Propanoic acid = HPr
HPr ==> H^+ + Pr^-
Set up an ICE chart and substitute into the below equation.
Ka = (H^+)Pr^-)/(HPr)
Solve for (H^+) and convert to pH.
(Pr^-) = (H^+)
You can find OH^- from (H^+)(OH^-) = 1E-14
%diss = (H^+)/(HPr)*100 = ??
HPr ==> H^+ + Pr^-
Set up an ICE chart and substitute into the below equation.
Ka = (H^+)Pr^-)/(HPr)
Solve for (H^+) and convert to pH.
(Pr^-) = (H^+)
You can find OH^- from (H^+)(OH^-) = 1E-14
%diss = (H^+)/(HPr)*100 = ??
Related Questions
For propanioic acid, HC3H5O2, Ka=1.3 x 10^-5, determine the concentration of the species present, th...
For propanoic acid (HC3H5O2, Ka = 1.3 10-5), determine the concentration of all species present, th...
For a solution that is 0.280 M HC3H5O2 (propanoic acid Ka=1.3*10^-5) and 0.0894 M HI, calculate the...
Calculate the pH after 0.011 mol NaOH is added to 1.00 L of each of the four solutions.
a) 0.100...