I have a question which asks...

Question

What is the Oxidation number of Nitrogen in Cu(NO3)2
I know the answer is 5+ but how do you get that??

Cu= 2+
O= 2- (Theres 3 of them so -2x3=-6...then, theres a two out of the brackets so 6- x 2 =-12)
+2 - (-12)= -10? And then what?
I think my method is wrong. :/ It's really frustrating and i've been at the same question for over an hour now.

Answer 1

See your post above.

Answer 2

Cu=2+
O=2-
Put x for N
Then ,
2(ie cu)+2×((x+3×-2))=0 (3 times O is there so 3×-2 , also both N and and O are there two times..so multiply them with two)
2+2x-12=0
2x=10
X=+5
Hope you understood🙂