Asked by arun
1) A region is bounded by the line y = x and the parabola y = x2 - 6x + 10. What is the volume of the solid generated by revolving the region about the x-axis?
Answers
Answered by
Reiny
find their intersection
x^2 - 6x + 10 = x
x = 2 or x = 5
volume = π [integral](x^2 - (x^2 - 6x + 10)^2 dx from 2 to 5
I would expand (x^2 - 6x + 10)^2
after that it just becomes a routine integration of simple terms and careful arithmetic.
x^2 - 6x + 10 = x
x = 2 or x = 5
volume = π [integral](x^2 - (x^2 - 6x + 10)^2 dx from 2 to 5
I would expand (x^2 - 6x + 10)^2
after that it just becomes a routine integration of simple terms and careful arithmetic.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.