Question
How do I write an equation of a line perpendicular to the graph of
-2y + x =-5 that passes through the point at (1,2)
Given the line -2y + x =-5, solve for y so the equation is in this form:
y = mx + b
Once you know the slope, m, you also know the slope of the perpendicular line.
As a reminder, the slope of the perpendicular line will be the negative reciprocal, or -1/m, m being the slope of the line above.
-2y + x =-5 that passes through the point at (1,2)
Given the line -2y + x =-5, solve for y so the equation is in this form:
y = mx + b
Once you know the slope, m, you also know the slope of the perpendicular line.
As a reminder, the slope of the perpendicular line will be the negative reciprocal, or -1/m, m being the slope of the line above.
Answers
Anonymous
XY 3x+2y=-6,z(3,2)