158.5 mL of a AgNO3 solution at 5.0M was combined with a 3.5M CaCl2 solution. 110.5g of AgCl was recovered. Given that the CaCl2 is the limiting reagent, how many milliliters of the 3.5M CaCl2 solution was used?

Question

158.5 mL of a AgNO3 solution at 5.0M was combined with a 3.5M CaCl2 solution.  110.5g of AgCl was recovered.  Given that the CaCl2 is the limiting reagent, how many milliliters of the 3.5M CaCl2 solution was used?

DrBob222 · Answer

Write the equation and balance it. Convert 110.5 g AgCl to moles AgCl, convert to moles CaCl2, then M = moles/L, solve for L and convert to mL.