Asked by Jas
An object is acted by 3 coplanar forces:30 newton to the north, 20 in the direction S20degrees E and 25 newton in a direction W20degrees S.Find the resultant
Answers
Answered by
Henry
S20DegE = 290Deg CCW.
W20DegS = 200Deg CCW.
X = hor. = 25cos200 + 20cos290,
X = -23.49 + 6.84 = -16.65N.
Y = ver. = 30 + 25sin200 + 20sin290,
Y = 30 - 8.55 - 18.79 = 2.66N.
tanA = Y/X = 2.66/-16.65 = -0.1596,
A=-9.07Deg = -9.07 +180 = 170.9Deg,Q2.
R = X/cosA = -16.65 / cos170.9 = 16.9N.
@ 170.9Deg.
W20DegS = 200Deg CCW.
X = hor. = 25cos200 + 20cos290,
X = -23.49 + 6.84 = -16.65N.
Y = ver. = 30 + 25sin200 + 20sin290,
Y = 30 - 8.55 - 18.79 = 2.66N.
tanA = Y/X = 2.66/-16.65 = -0.1596,
A=-9.07Deg = -9.07 +180 = 170.9Deg,Q2.
R = X/cosA = -16.65 / cos170.9 = 16.9N.
@ 170.9Deg.
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