Asked by tara
A student determined the chloride content of a commercial salt by using the Mohr method. A 0.5324 -g sample of the salt was dissolved in distilled water and diluted to a final volume of 250. mL. A 25.-mL aliquot of the analyte solution was then titrated against a standard 0.0408 M AgNO3(aq) solution to the chromate end-point. A blank-corrected volume of 23.56 mL was recorded. Calculate the percent chloride in the sample.
Answers
Answered by
DrBob222
moles AgNO3 = M x L = ??
moles Cl^- is the same since the equation is a 1:1 ratio. Cl^- + Ag^= => AgCl.
grams Cl = moles Cl^- x atomic mass Cl.
%Cl^- = (mass Cl^-/mass sample)*100 = ??
Note: mass of the sample is 1/10 x 0.5324g since you took a 25 mL aliquot of the 250 mL sample.
moles Cl^- is the same since the equation is a 1:1 ratio. Cl^- + Ag^= => AgCl.
grams Cl = moles Cl^- x atomic mass Cl.
%Cl^- = (mass Cl^-/mass sample)*100 = ??
Note: mass of the sample is 1/10 x 0.5324g since you took a 25 mL aliquot of the 250 mL sample.
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