Asked by Pob
If 17.0 mL of 0.590 M CaCl2 are mixed with 46.6 mL of 0.480 M CaCl2, calculate the molarity of each ion in the final solution? Assume the volumes are additive.
Answers
Answered by
DrBob222
moles soln 1 = M x L = ??
moles soln 2 = M x L = ??
M CaCl2 = total moles/total L.
M Ca^+2 = M CaCl2
M Cl^- = 2 x M CaCl2.
moles soln 2 = M x L = ??
M CaCl2 = total moles/total L.
M Ca^+2 = M CaCl2
M Cl^- = 2 x M CaCl2.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.