Question
If 17.0 mL of 0.590 M CaCl2 are mixed with 46.6 mL of 0.480 M CaCl2, calculate the molarity of each ion in the final solution? Assume the volumes are additive.
Answers
moles soln 1 = M x L = ??
moles soln 2 = M x L = ??
M CaCl2 = total moles/total L.
M Ca^+2 = M CaCl2
M Cl^- = 2 x M CaCl2.
moles soln 2 = M x L = ??
M CaCl2 = total moles/total L.
M Ca^+2 = M CaCl2
M Cl^- = 2 x M CaCl2.
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