Asked by Anonymous
The scores on the Webster test are approximately normal with u=100 and o=15. The proportion of adults with scores between 90 and 110 is closest to??
Answers
Answered by
PsyDAG
Z = (score-mean)/SD
After calculating the Z scores, find table in the back of your statistics text labeled something like "areas under normal distribution" to find the related proportion.
After calculating the Z scores, find table in the back of your statistics text labeled something like "areas under normal distribution" to find the related proportion.
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