You want 0.700M in Na^+ which means 1/3 of that for Na3PO4 or 0.700/3 = ??
How many moles do you want? That will be ??M x L = xx moles.
How many grams is that.
moles = grams/molar mass.
How many moles do you want? That will be ??M x L = xx moles.
How many grams is that.
moles = grams/molar mass.
1. Molar mass of Na3PO4:
- Na (sodium) has a molar mass of 22.99 g/mol (from the periodic table)
- P (phosphorus) has a molar mass of 30.97 g/mol (from the periodic table)
- O (oxygen) has a molar mass of 16.00 g/mol (from the periodic table)
Adding up the molar masses, we get:
Molar mass of Na3PO4 = (3 * Na) + P + (4 * O)
Molar mass of Na3PO4 = (3 * 22.99) + 30.97 + (4 * 16.00)
Molar mass of Na3PO4 = 163.94 g/mol
2. Concentration of Na+ ions:
The concentration, C (in moles per liter), is given as 0.700 M, which means there are 0.700 moles of Na+ ions in 1 liter of the solution.
3. Volume of the solution:
The volume, V (in liters), is given as 500 mL. To convert mL to liters, divide by 1000:
V = 500 mL / 1000 = 0.500 L
Now, we can calculate the amount of Na3PO4 needed:
Amount of Na3PO4 (in moles) = Concentration (in moles per liter) * Volume (in liters)
Amount of Na3PO4 = 0.700 * 0.500
Finally, to calculate the grams of Na3PO4 needed, we can use the molar mass:
Grams of Na3PO4 = Amount of Na3PO4 (in moles) * Molar mass of Na3PO4
Grams of Na3PO4 = (0.700 * 0.500) * 163.94
Evaluate the expression to find the answer.