L = Lo + k*Lo(T - To).
Lo = Initial length.
To = Initial temperature.
L = 10 + k*10(100 - 24) = 10.015,
10 + 760k = 10.015,
760k = 10.015 - 10 = 0.015,
k = 1.974*10^-5 = Coefficient of linear expansion.
a. L=1000 + 1.974*10^-5*1000(100 - 24),
L = 1000 + 1.974*10^-5*76000,
L = 1000 + 1.50024 = 1001.500cm.
When you converted to cm, you multiplied by 100. Therefore you'll
have to multiply the 0.015 by 100 also.
Then you'll get 1000 + 1.5 = 1001.5cm,
A bar made of a particular metallic alloy has a length of 10 cm at a temperature of 24 oC and a length of 10.015 cm at the boiling point of water.
(a) If a second bar made of the same material were 10 m at 24 oC, how much longer would this bar be at the boiling point of water?
The answer has to be in cm. So i converted 10m to cm, 1000 and then put on the .015. Ended up with 1000.015. and that's wrong. I need to find delta L. I know this is dealing with thermal expansion, but I need help figuring out how to do this.
1 answer
1 answer