Asked by Mari
A .50kg ball is rolling on a frictionless surface at a speed of .75m/s. it collides with a second ball with a mass of 1kg which is also moving in the same direction as the first ball with a speed of .38m/s. After the collision the firt ball continues at a reduced speed of .35m/s. what is the new speed of the second ball after the collision?
Answers
Answered by
drwls
The new speed of the second ball is whatever conserves linear momentum.
Call it V2f
M1*V1i + M2*V2f = M1*V1f + M2*V2f
0.50*0.75 + 1.00*0.38 = 0.50*0.35 + 1.00*V2f
V2f = 0.58 m/s
Call it V2f
M1*V1i + M2*V2f = M1*V1f + M2*V2f
0.50*0.75 + 1.00*0.38 = 0.50*0.35 + 1.00*V2f
V2f = 0.58 m/s
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