Find the linear speed of the bottom of a test tube in a centrifuge if the centripetal acceleration there is 5.5×104 times the acceleration of gravity. The distance from the axis of rotation to the bottom of the test tube is 8.0 .

Answer 1

V^2/R = 5.5*10^4*9.8 m/s^2.

R must be in meters. You do not say what the units are.

Solve the equation above for V.

Answer 2

20.7

Answer 3

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