Asked by Anonymous
In a circle whose radius is 6, find the area of a sector, in terms of pi, whose center angle contains 30 degrees
Answers
Answered by
Henry
As = ((pi/6)/2pi)*pi *6^2
As = 1/6 * 1/2 * 36pi = 3pi.
As = 1/6 * 1/2 * 36pi = 3pi.
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