A movie theater charges $7 for adults, $5 for school-age children, and $3 for babies. A group of people went to the theater. There were the same number of school-age children as babies and the number of adults was the same as school-age children and babies combined. If the group paid $1562, how many babies were in the group ?
2 answers
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same number of school-age children as babies
x=number of school-age children
x=number of babies
number of adults was the same as school-age children and babies combined
y=number of adults
y=x+x
y=2x
$7(2x) + $5(x)+ $3(x) = $1562
similar problem - look at example 1:
http://www.algebra-class.com/algebra-word-problems.html
x=number of school-age children
x=number of babies
number of adults was the same as school-age children and babies combined
y=number of adults
y=x+x
y=2x
$7(2x) + $5(x)+ $3(x) = $1562
similar problem - look at example 1:
http://www.algebra-class.com/algebra-word-problems.html
1 answer