Question

the dimensions of a rectangle are such that its length is 3 inches more than its width. if the length were double and if the width were decreased by 1 inch, the area would be increased by 66inches ^2. What are the length and width of the rectangle?
Let w = width and w+3 = length.

2(w+3)(w-1) - w(w+3) = 66

Solve for w, then w+3.
Can someone please explain what the -w(w+3) in the solution stands for?

Related Questions

The length of a rectangle is twice the width. If the length is increased by 4 inches and the width i... A rectangle is 4 inches wide by 7 inches long. When the length and width are increased by the same a... The length of a rectangle is twice the width.  If the length is increased by 4 inches and the width... The diagram represents an enlargement of a rectangle by a scale factor of 4. A small rectangle ha...