the dimensions of a rectangle are such that its length is 3 inches more than its width. if the length were double and if the width were decreased by 1 inch, the area would be increased by 66inches ^2. What are the length and width of the rectangle?

Answer 1

Let w = width and w+3 = length.

2(w+3)(w-1) - w(w+3) = 66

Solve for w, then w+3.

Answer 2

Can someone please explain what the -w(w+3) in the solution stands for?