Question
a 2 kg block slides down a frictionless incline from point A to point B. A force(magnitude P=3N) acts on the block between A and B, as shown. Points A and B are 2 m apart. If the kinetic energy of the block at A is 10 J, and the work done by gravity is 20J, what is the KE of the block at B?
Answers
KE increases going from A to B by an amount
(Work done by gravity) + P*(2 m)
This assumes that P is aligned with the direction of motion. Otherwise you also need a cosine factor.
KE(final) = 10 J + 20 J + 6 J = ___
(Work done by gravity) + P*(2 m)
This assumes that P is aligned with the direction of motion. Otherwise you also need a cosine factor.
KE(final) = 10 J + 20 J + 6 J = ___
good
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